ম্যাথমেটিক্স MCQ,30শে জুন, 2023 IBPS RRB পরীক্ষার জন্য

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ম্যাথমেটিক্স MCQ

Directions (1-5): The following questions are accompanied by two statements (I) and (II). You have to determine which statements(s) is/are sufficient/necessary to answer the questions.

(a) Statement (I) alone is sufficient to answer the question but statement (II) alone is not sufficient to answer the question.

(b) Statement (II) alone is sufficient to answer the question but statement (I) alone is not sufficient to answer the question.

(c) Both the statements taken together are necessary to answer the question, but neither of the statements alone is sufficient to answer the question.

(d) Either statement (I) or statement (II) by itself is sufficient to answer the question.

(e) Statements (I) and (II) taken together are not sufficient to answer the question.

Q1. An article is marked 35% above its cost price, find the cost price of the article.

Statement I: Discount allowed on article is Rs.190 more than profit earned on the article.

Statement II: Ratio of selling price of the article to marked price of the article is 4 : 5.

Q5. Deepak is 20% less efficient than Dharam. Find efficiency of Shivam.

Statement I: Shivam and Dharam working together can complete a piece of work in  days and Deepak and Shivam working together an complete same piece of work in  days.

Statement II: Deepak is 60% less efficient than Shivam and Dharam working alone can complete a piece of work in 80 days.

Q3. Asif invested Rs.80000 across two schemes – A & B offering SI in the ratio 5 : 3 respectively. Find total interest earned by him.

Statement I: Rate of interest offered by scheme – B is twice of that of offered by scheme – A and period of investment in both schemes is 4 years.

Statement II: Interest received from scheme – B is Rs.6000 more than interest received from scheme – A.

Q4. Average of present age of Aman, Bhanu and Chaman is 34 years. Find present age of Chaman.

Statement I: Aman’s present age is 100% more than Chaman’s present age and ratio of Bhanu’s age 6 years hence to Chaman’s present age is 2 : 1.

Statement II: Sum of Aman’s and Bhanu’s present age is 78 years.

Q5. Ratio of length of train – A and train – B is 4 : 5. Find speed of train – A.

Statement I: Train – A can cross a 500m long platform in 28 seconds and train – A crosses train – B while running in same direction in 54 seconds.

Statement II: Train – B can cross a pole in 15 seconds.

Direction (6-10): – Bar graph shows total number of students (Medical and Non-medical) in section A and section B in 4 different years. Table has 3 columns, first shows year, column second mention the ratio of student having medical side to that of non-medical side. Column III shows percentage of Medical students in section A, out of total medical students.

Q6.       Calculate the percentage of medical student from section B out of total medical students in year 2012.

(a) 0%

(b) 25%

(c) 40%

(d) 50%

(e) None of these

Q7.       What is the ratio of medical student of section B to non-medical student of section A of year 2014.

(a) 1 : 1

(b) 2 : 3

(c) 5 : 3

(d) 3 : 2

(e) 2 : 5

Q8.      What is the ratio of total number of medical students to total number of non medical students of all these years together?

(a) 145 : 101

(b) 29 : 21

(c) 7 : 5

(d) 4 : 3

(e) None of these

Q9.       In year 2013, 10% of those who have medical, qualified PMT & 25% of those who have non-medical qualified JEE, then calculate total percentage of students who either qualified JEE or PMT in year 2013.

(a) 54%

(b) 18%

(c) 20%

(d) 16%

(e) 44%

Q10.    What is the % of non-medical students of section B with respect to total students of section B in year 2015.

(a) 21%

(b) 16%

(c) 13%

(d) 17%

(e) 19%

ম্যাথমেটিক্স MCQ সমাধান

S1. Ans.(c)
Sol. Let cost price of the article be Rs.100x.
So, marked price of the article =100x×135/100=Rs.135x
and let selling price of the article be Rs.y.
From I:
ATQ,
(135x – y) – (y – 100x) = 190
135x – y – y + 100x = 190
235x – 2y = 190 _________ (i)
From II:
y/135x=4/5
⇒ y = 108x _________ (ii)
On solving (i) & (ii), we get:
x = 10
So, cost price of the article = Rs.100x
= Rs. 1000
Hence, both statements taken together are necessary to answer the question.

S2. Ans.(a)
Sol. Let efficiency of Dharam be ‘5x units/day’.
So, efficiency of Deepak =5x×80/100
= ‘4x units/day’
Now, let efficiency of Shivam be ‘y units/day’.
From I:

So,
5x + y = 15 __________ (i)
4x + y = 14 __________ (ii)
On solving (i) & (ii), we get:
x = 1, y = 10
So, efficiency of Shivam = 10 units/day
From II:
ATQ,
y×40/100=4x
y = 10x
Total work = 80 × 5x = 400x units
Hence, statement I alone is sufficient to answer the question.

S3. Ans.(c)
Sol. Amount invested by Asif in scheme – A =80000×5/8=Rs.50000
Amount invested by Asif in scheme – B =80000×3/8=Rs.30000
From I & II:
Let rate of interest offered by scheme – B be 2R% p.a.
So, rate of interest offered by scheme – A =2R×1/2=R% p.a.
ATQ,
(30000×2R×4)/100-(50000×R×4)/100=6000
⇒ 2400R – 2000R = 6000
400R = 6000
R = 15%
So, total interest received by Asif =(30000×2×15×4)/100+(50000×15×4)/100
= 36000 + 30000
= Rs. 66000
So, both statements together are sufficient to answer the question.

S4. Ans.(d)
Sol. Let present age of Aman, Bhanu and Chaman be ‘x years’, ‘y years’ & ‘z years’ respectively.
So, x + y + z = 34 × 3
x + y + z = 102 ________ (i)
From I:
x=z×200/100
x = 2z __________ (ii)
And, (y+6)/z=3/2
2y + 12 = 3z
2y = 3z – 12
y=(3z-12)/z ________ (iii)
On solving (i), (ii) & (iii), we get:
z = 24 years
From II:
x + y = 78 _________ (iv)
On solving (i) & (iv), we get:
z = 24 years
Hence, either statement I alone or statement II alone is sufficient to answer the question.

S5. Ans.(c)
Sol. Let length of train – A & train – B be ‘4x’ & 5x’ meters respectively.
From I & II:
Let speed of train – A & train – B be ‘V1 m/sec’ & ‘V2 m/sec’ respectively.
ATQ,
(4x+500)/28=V_1 ________ (i)
And, (4x+5x)/54=V_1-V_2 _________ (ii)
Put value of (i) in (ii):
9x/54=(4x+500)/28-V_2
⇒ V_2=(x + 125)/7-x/6
V_2=(6x+750-7x)/42
V_2=(750-x)/42 _________ (ii)
And, 5x/15=V_2
V_2=x/3 _______ (iii)
On solving (ii) & (iii), we get:
x = 50
Put value of x in (i):
(200+500)/28=V_1
⇒ V1 = 25
Hence, both statements taken together are sufficient to answer the question.

S6. Ans.(b)
Sol.
Total number of medical student = 4/7×[150+200]
= 4/7×350 = 200
Total number of medical student from section A = 75/100×200 = 150
Hence number of medical student in section B = 200 – 150 = 50
Required% = 50/200×100 = 25%

S7. Ans.(d)
Sol.
Number of medical student from section A in year 2014
= 1/2×(2/3×360)
= 120
∴ Number of non-medical student from section A in year 2014
= 200 – 120 = 80
Number of medical student of section B
= (2/3×360 –120)
= 120
Required ratio = 120 : 80
= 3 : 2

S8. Ans.(a)

Sol.
No. of medical student No. of non medical student
Year 2012, 4/7×350 = 200 150
Year 2013, 7/15×300 = 140 160
Year 2014, 2/3×360 = 240 120
Year 2015, 29/44×220 = 145 75
Required ratio = (200 + 140 + 240 + 145) : (150 + 160 + 120 + 75)
= 725 : 505
= 145 : 101

S9. Ans.(b)
Sol.
In year 2013, Number of students have medical = 7/15×300 = 140
Number of students who qualified PMT= 10/100×140 = 14
Number of students who have non-medical = 8/15×300 = 160
Number of students who qualified JEE = 25/100×160 = 40
Required % = 54/300×100 = 18%

S10. Ans.(c)
Sol.
Year 2015, Medical students from section A
= 40/100×29/44×220 = 58
∴ Medical students from section B = 145 – 58 = 87
Number of non-medical students in section B in given year= 100 – 87 = 13
Required % = 13/100×100 = 13%

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