AFCAT Maths Questions with Detailed Solution for 2025 Exam

In this article, Air Force Aspirants will find the important AFCAT Maths Questions for the upcoming AFCAT 2025 Examination. As candidates prepare for the Air Force Common Admission Test (AFCAT) in 2025, mastering the mathematics section is crucial for success. The AFCAT Maths alone can provide 60 Marks to candidates.

AFCAT Maths Questions

We will explore some of the most important questions that have previously appeared in AFCAT math exams, along with detailed solutions, tips and strategies to tackle them effectively. Whether you are revising key concepts or looking for practice problems, these questions will help you gain confidence and enhance your performance for the AFCAT Exam. on test day. Let’s dive into the essential AFCAT math questions you should focus on to excel in the AFCAT 1 2025!

Q1. Rohan’s present age is times of the age of his mother. After five years, he will be one half
of the age of his mother. How old is his mother at present?
(a) 31 years
(b) 33 years
(c) 35 years
(d) 37 years

S1. Ans (c)
Sol.
Let the present age of Rohan be R years and his mother’s age be M years.
Given:
R = (3/7)M
After 5 years, R + 5 = 1/2 (M + 5)
Substitute R = (3/7)M in the second equation:
(3/7)M + 5 = 1/2 (M + 5)
Multiply both sides by 14:
6M + 70 = 7(M + 5)

6M + 70 = 7M + 35
M = 35 years

Q2. Aman takes 36 minutes more than Sudhanshu to cover a distance of 130km. If Aman
doubles his speed, he takes 42 minutes less than Sudhanshu to cover the same distance.
To cover the distance of 195 km, how much time (in hours) will Sudhanshu take his
same speed?
(a) 2
(b) 2
(c) 2
(d) 3

S2. Ans (d)
Sol.
For A =>
Speed:                   1         2
Time:                     2         1
Difference time =36+42=78min
ATQ- 1=78
2=78×2=156 min.
Sudhansu takes time =156-36=120min = 2 hours.
Speed =130/2=65km/h
Sudhanshu take time =195/65=3hours.

Q3. The compound interest on a certain amount for 2 years at 4% per annum is Rs.1,020, if
interest is compounded annually. Find the simple interest on that amount for 2 years at
4% per annum?
(a) Rs.800
(b) Rs.850
(c) Rs.950
(d) Rs.1,000

S3. Ans (d)
Sol.
Given: Compound interest for 2 years at 4% = ₹1,020
Let the principal amount be ₹P.
Formula for compound interest:
CI = P × (1 + R/100) T – P
Substitute values:
1,020 = P × (1 + 4/100) 2 – P
1,020 = P × (1.04) 2 – P
1,020 = P × (1.0816 – 1)
1,020 = 0.0816P
P = 1,020 / 0.0816 = ₹12,500
Now, calculate simple interest:
SI = P × R × T / 100
SI = 12,500 × 4 × 2 / 100 = ₹1,000
Hence, the simple interest on that amount for 2 years is ₹1,000.

Q4. Anju spends 16% of her monthly income on rent, 22% of it on groceries, 14% of it on
children’s education and 60% of the remaining on other item. If Rs.22,852 is left with
her at the end of the month, then what is her monthly income (in Rs.)?
(a) 90,450
(b) 1,19,020
(c) 98,500
(d) 99,000

S4. Ans (b)
Sol.
Let Anju’s monthly income be ₹X.
Expenses:
Rent = 16% of X
Groceries = 22% of X
Children’s education = 14% of X
Remaining amount = X – (16% + 22% + 14%) of X = X – 52% of X = 48% of X
Amount spent on other items = 60% of 48% of X = 28.8% of X
Amount left = X – (52% of X + 28.8% of X) = 19.2% of X
Given that 19.2% of X = ₹22,852
X = ₹22,852 / 0.192 = ₹1,19,020
Hence, Anju’s monthly income is ₹1,19,020.

Q5. Seven years ago, the sum of the ages of a mother and her daughter was 46 years. The
ratio of their present ages is 3:1. What is the present age of the daughter?
(a) 11 years
(b) 13 years
(c) 15 years
(d) 17 years

S5. Ans (c)
Sol.
Let the present ages of the mother and daughter be 3x and x years respectively.
Seven years ago, their ages were (3x – 7) and (x – 7).
According to the given condition,
(3x – 7) + (x – 7) = 46
4x – 14 = 46
4x = 60
x = 15
Present age of the daughter = 15 years

Q6. Ajay, Bablu and Chirag can complete a certain work in 21, 28 and 15 days respectively.
Ajay and Chirag started the work while Bablu joined them after 5 days and worked with
them till the completion of the work. For how many days Bablu worked?
(a) 2 days
(b) 2 days
(c) 3 days
(d) 4 days

S6. Ans (b)
Sol.
Ajay’s work rate = 1/21 work/day
Bablu’s work rate = 1/28 work/day
Chirag’s work rate = 1/15 work/day
LCM of 21,28,15 = 420
Efficiency of A,B and C
A B C
20  15  28
Ajay And Chirag both working 5 days = (20+28) ×5=240
Remaining work complete by Ajay Bablu and Chirag =180/63
=20/7 = 2(6/7) days

Q7. A chemist prepared 50 grams of a medicine by mixing two ingredients ‘P’ and ‘Q’. Rate
of ‘P’ is Rs.150 per 10 gm and that of ‘Q’ is Rs.500 per 100 gm. ‘P’ and ‘Q’ are mixed in
such a way that the cost of the resulting medicine is Rs.12 per gm. What I the quantity of
‘P’ (in grams) in the medicine?
(a) 15
(b) 20
(c) 25
(d) 35

S7. S3. Ans (d)
Sol.
Let the quantity of P in the mixture be x grams.
Quantity of Q = 50 – x grams
Cost of P = ₹150 per 10 grams = ₹15 per gram
Cost of Q = ₹500 per 100 grams = ₹5 per gram
Total cost = (15x) + (5(50 – x)) = 15x + 250 – 5x = 10x + 250
Given cost of the resulting medicine = ₹12 per gram
12 × 50 = 10x + 250
600 = 10x + 250
10x = 600 – 250 = 350
x = 35 grams
Hence, the quantity of P is 35 grams.

Q8. Rs.1,800 is divided among Nitin, Tushar and Gitanjali. The share of Gitanjali is of the
sum of the shares of Nitin and Tushar. What is the share of Gitanjali?
(a) 700
(b) 750
(c) 800
(d) 1000

S8. Ans (d)
Sol.
Given:
Share of Gitanjali = 5/4 of (N + T)

Solution:
Let Gitanjali’s share = G
N + T + G = ₹1,800
let the share of Nitin and Tushar =x
Nitin Tushar      Gitanjali
x    x              2x ×5/4 = 5x/2
Total Sum = x + x + 5x/2 = 1800
9x =3600
x = 400
Share of Gitanjali =400 × 5/2=1000.

Q9. The average salary of 28 employees is recorded as Rs.16,584. If the salary of an
employee with value Rs.14,526 was entered wrongly as Rs.41,238, then the corrected
average is:
(a) 16238
(b) 15630
(c) 15532
(d) 14480

S9. Ans (b)
Sol.
Total salary of 28 employees (recorded) = 28 × 16,584 = ₹464,352
Corrected salary = ₹464,352 – ₹41,238 + ₹14,526 = ₹437,640
Corrected average = ₹437,640 / 28 = ₹15,630

Q10. The income of Anand is 30% more than the income of Mayank and the income of
Radhika is 70% of the combined income of Anand and Mayank. By what percentage is
the income of Radhika more than that of Anand? (Correct to one decimal place)
(a) 16.5
(b) 19.6
(c) 21.8
(d) 23.8

S10. Ans (d)
Sol.
Let Mayank’s income be ₹100.
Anand’s income = 130% of Mayank’s income = ₹130.
Combined income of Anand and Mayank = ₹100 + ₹130 = ₹230
Radhika’s income = 70% of ₹230 = ₹161
Income of Radhika more than that of Anand = ₹161 – ₹130 = ₹31
Percentage increase = (31/130) × 100 = 23.8%
Hence, Radhika’s income is 23.8% more than that of Anand.