NHPC-JE'21 CE: Daily Practices Quiz. 06-Oct-2021

Know your strengths and practice your concepts with this quiz on NHPC JE Recruitment 2021. This quiz for NHPC JE Recruitment 2021 is designed specially according to NHPC Syllabus 2021.

Quiz: Civil Engineering
Exam: NHPC-JE
Topic: Miscellaneous

Each question carries 1 mark
Negative marking: 1/4 mark
Time: 8 Minutes

Q1. In an under-reinforced section, the value of actual neutral axis xa and the critical neutral axis xc are related as:
(a) x_a=x_c
(b) x_a>x_c
(c) x_a>2x_c
(d) x_a<x_c

Q2. Reusable wastewater from residential, commercial and industrial bathroom sinks, bath tub shower drains and clothes washing equipment drains, is known as
(a) Blue water
(b) Black water
(c) Brown water
(d) Grey water

Q3. Crushing strength of a good building stone should be more than:
(a) 50 MPa
(b) 150 MPa
(c) 100 MPa
(d) 200 MPa

Q4. The fore bearing of a line is 145°30’. What is its back bearing?
(a) 34°30’
(b) 325°60’
(c) 325°30’
(d) 324°30’

Q5. The total length of bar having hook at both the ends is:
(a) L + 9D
(b) L + 24D
(c) L + 18D
(d) L + 12D

Q6. The absolute minimum radius of curve for safe operation, for a speed of 100 kmph is:
(a) 260 m
(b) 440 m
(c) 360 m
(d) 320 m

Solutions

S1. Ans.(d)
Sol. Actual neutral axis = x_a
critical neutral axis = x_c
x_a<x_c→ under reinforced
x_a=x_c→ Balance section
x_a>x_c→ Over reinforced

S2. Ans.(d)
Sol. Reusable wastewater from residential, commercial and industrial bathroom sinks, bath tub shower drains and clothes washing equipment drains, is known as grey water.

S3. Ans.(c)
Sol.
– Crushing strength of a good building stone should be more than 100 MPa or 1000 kg/cm².
– Crushing test is performed to determine crushing strength.

S4. Ans.(c)
Sol. F.B = 145°30’
B.B = ?
F.B < 180°, hence
B.B = F.B + 180°
= 145°30’ + 180°
= 325° 30’

S5. Ans.(c)
Sol. The total length of bar having hook at both the ends is L + 18D.
Where L = length of bar
D = Diameter of bar.

S6. Ans.(c)
Sol. Given,
Minimum design speed V_min = 100 kmph
e_max = 0.07, f = 0.15 (Normally)
Absolute minimum radius (R_Absolute)→
R_Absolute=V^2/127(e+f)
=(100)^2/127(0.07+0.15)
= 357.9 m ≃ 360 m