UPPCL-JE’21 EE: Daily Practices Quiz 03-Nov-2021

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UPPCL-JE’21 EE: Daily Practices Quiz

UPPCL-JE’21 EE: Daily Practices Quiz 03-Nov-2021

Each question carries 1 mark.
Negative marking: 1/4 mark
Total Questions: 06
Time: 06 min.

Q1. If the speed of a DC machine is doubled and the flux remains constant, the generated e.m.f.
(a) Is doubled
(b) Is halved
(c) Remains the same
(d) None of the above

Q2. A 15 V source is connected across a 12 Ω resistor. How much energy is used in 3 minutes?
(a) 5.6 Wh
(b) 938 Wh
(c) 0.938 Wh
(d) 56.25 Wh

Q3. When the speed at which a conductor is moved through a magnetic field is increased, the induced voltage
(a) Remains constant
(b) Increases
(c) Decreases
(d) Reaches zero

Q4. Three lights are connected in parallel across a 120-volt source. If one light burns out,
(a) The remaining two will not glow
(b) The remaining two will glow dimmer
(c) The remaining two will grow brighter
(d) The remaining two will glow with the same brightness as before

Q5. Two capacitor C1 and C2 have C1=20μ F and C2 = 30μ F, are connected in parallel
across a 100V source. The net capacitance of the circuit is?
(a) 50 μ F
(b) 10 μ F
(c) 12 μ F
(d) 60 μ F

Q6. A 100mA meter has accuracy of +2%. Its accuracy while reading 50mA will be:
(a) +1%
(b) +2%
(c) +4%
(d) +20%

SOLUTIONS

S1. Ans.(a)
Sol. E_b α ϕN
ACQ: ?=constant
∴E_b α N
So, if speed is doubled then generated emf will also be doubled.

S2. Ans.(c)
Sol. P=V^2/R=(15)^2/12=225/12 W
And t=3 minutes=3/60 hours
∴W=P×t=225/12×3/60=0.938 Wh

S3. Ans.(b)
Sol. e=BlV sin⁡Ө
So, e α v
So, when speed is increased the induced voltage will also increase.

S4. Ans.(d)
Sol. Three lights are connected in parallel across a 120-volt source. If one light burns out, the remaining two will glow with the same brightness as before because the voltage across other two light will not change.

S5. Ans.(a)
Sol. C_eq=C_1+C_2
= 30μF + 20μF
= 50 μF

S6. Ans.(c)
Sol. Error = 100 mA ×(±2)/100= ±2mA
% Error = (±2mA)/50mA×100= ±4%

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