UPPCL-JE’21 EE: Daily Practices Quiz 16-Nov-2021

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UPPCL-JE’21 EE: Daily Practices Quiz

UPPCL-JE’21 EE: Daily Practices Quiz 16-Nov-2021

Each question carries 1 mark.
Negative marking: 1/4 mark
Total Questions: 06
Time: 06 min.

Q1. ………is used for execution of a program.
(a) Data memory
(b) User memory
(c) Executive memory
(d) System memory

Q2. …. is a conductor from which tapings are taken for supply to the consumers?
(a) Delivery unit
(b) Distributor
(c) Service main
(d) Feeder

Q3. For which type of motor are both the given characteristics true?
1. No-load condition is dangerous.
2. Variable speed.
(a) Shunt motors
(b) Series motors
(c) Differential compound motors
(d) Cumulative compound motors

Q4. An ac voltage source of 250 V(rms) supplies active power of 300 watts and reactive power of 400 VAR. Find the value of current(rms) drawn by the source.
(a) 10 A
(b) 6 A
(c) 4 A
(d) 2 A

Q5. Which one of the following correct?
(a) Synchronous motor is supplied with D.C. voltage in the armature winding
(b) Synchronous motor is supplied with ac voltage in the field winding
(c) Synchronous motor is supplied with rectified voltage in the armature winding
(d) Synchronous motor is supplied with dc voltage in the filed winding

Q6. In order to eliminate the fifth harmonic voltage from the phase voltage of an alternator, the coil should be pitched by:
(a) 72°
(b) 36°
(c) 15°
(d) 18°

SOLUTIONS

S1. Ans.(d)
Sol. Main memory or RAM is used to store the program while it is executing and to store the data that the program is working with.

S2. Ans.(b)
Sol. A distributor is a conductor from which tapings are taken for supply to the consumers.
NOTE: The current through a distributor is not constant because tapings are taken at various places along its length.

S3. Ans.(b)
Sol. DC series motor:
at no load or at light load there is a possibility of dangerously high speed, which may damage the rotor. Hence, dc series motor should never be run at no load.
dc series motor has high torque at low speed and vice – versa.
This property makes the dc series motor useful for traction purpose.

S4. Ans.(d)
Sol. tan ϕ =400/300=4/3
∴cos ϕ =3/5
P= V_rms I_rms cos⁡ϕ
⇒300= 250 ×I_rms×3/5
⇒I_rms= 2 A.

S5. Ans.(d)
Sol. in synchronous motor
3-ϕ AC supply on → Stator
DC supply on → Rotor

S6. Ans.(b)
Sol. To eliminate n^th harmonic, the displacement angle (β) = (180°)/n
According to Question,
To eliminate 5th harmonic, β = (180°)/5=36°