Quiz: Mechanical Engineering
Exam: UPPSC Lecturer
Topic: SOM & FM
Each question carries 1 mark
Negative marking: 1/4 mark
Time: 6 Minutes
Q1. In the design of singly reinforced simply supported beams, the maximum bending moment will be (Given W is the maximum load and “I” is the length):
(a) Wl/64
(b) W/8l²
(c) Wl^2 \/8
(d) W^2 \/32
Q2. What is the power (in kW) transmitted by a rotating shaft? (Where: P = power, N= Speed in rpm and T = Torque transmitted)
(a) 2πNT/60
(b) 2πNT²/60000
(c) NT/60000π
(d) 2πNT/60000
Q3. The angle of twist proportional to twisting moment.
(a) Directly
(b) Inversely
(c) Both (A) & (B)
(d) None of these
Q4. Discharge formula for triangular weir is:
(a) 8/15 Cd √2g H^(5/2)
(b) 8/15 Cd √2g H^(3/2)
(c) 8/15 Cd √2g H^(1/2)
(d) 8/15 Cd √2g H^
Q5. Pitot tube is used to measure………….
(a) Discharge
(b) Average velocity
(c) Velocity at a point
(d) Pressure at a point
Q6. Which one of the following is not a non-dimensional parameter?
(a) Froude number
(b) Mach number
(c) Chezy’s coefficient
(d) Darcy -Weisbach friction factor
Solutions
S1. Ans. (c)
Sol.
S2. Ans. (d)
Sol. Power (P) = 2πNT/60 (watts)
P= 2πNT/60×1/10³ (Kilo watt)
P=2πNT/60000
S3. Ans. (a)
Sol. T/J=τ/R=Gθ/L
T α Q
S4. Ans. (a)
Sol. discharge for triangular notch (Q)
Q = 8/15 C_d √2g H^(5/2)
S5. Ans. (c)
Sol. Pitot tube is used to measure velocity at a point.
V=C_v √2gH
S6. Ans. (c)
Sol. (i) Fr = V/√gy = (m/sec)/(√(m/sec²) × m) = (m/sec)/(m/sec) = 1
(ii) Mach Number – (Ma) = V/√(k/ρ)
= (m/sec)/(√(N/m^2 ) × m³/kg) = (m/sec)/(√((kg.m)/(sec^2×m²)) ×m³/kg) = 1
(iii) chezy’s coefficient (c) = √(8g/f)
= √(m/sec²)
= [L^(1/2) T^(-1)]