The “Top 15 Arithmetic MCQs for Odisha Police Constable Exam” covers essential mathematical concepts critical for competitive exam preparation. This set includes questions from various topics such as Pipe & Cistern, Number System, Time & Work, Simple Interest (SI) & Compound Interest (CI), Calendar Days Calculation, Profit & Loss, Simplification, Probability, Time & Distance, Mensuration, LCM & HCF, and Boat & Stream. Each question is crafted to challenge candidates’ problem-solving skills and enhance their arithmetic proficiency. These MCQs offer a comprehensive approach to mastering key topics, providing step-by-step solutions and detailed explanations to aid in exam readiness.
Top 15 Arithmetic MCQs For Odisha Police Constable
Q1. A pipe can fill a tank in 8 hours and another pipe can fill it in 12 hours. How long will it take to fill the tank if both pipes are opened together?
(a) 4.8 hours
(b) 5 hours
(c) 4 hours
(d) 6 hours
S1. Ans: (a) 4.8 hours
Sol:
Rate of Pipe 1 = 1/8, Rate of Pipe 2 = 1/12
Combined rate = 1/8 + 1/12 = 3/24 + 2/24 = 5/24
Time = 24/5 = 4.8 hours
Q2. What is the LCM of 12, 15, and 18?
(a) 180
(b) 90
(c) 360
(d) 60
S2. Ans: (a) 180
Sol:
Prime factorization of 12 = 2² × 3
Prime factorization of 15 = 3 × 5
Prime factorization of 18 = 2 × 3²
LCM = 2² × 3² × 5 = 180
Q3. A person travels 120 km in 3 hours. What is the speed in km/h?
(a) 30 km/h
(b) 40 km/h
(c) 50 km/h
(d) 60 km/h
S3. Ans: (b) 40 km/h
Sol:
Speed = Distance / Time = 120 km / 3 hours = 40 km/h
Q4. If the simple interest on ₹1500 for 2 years is ₹300, what is the rate of interest?
(a) 8%
(b) 10%
(c) 12%
(d) 15%
S4. Ans: (b) 10%
Sol:
Simple Interest (SI) = P × R × T / 100
300 = 1500 × R × 2 / 100
R = (300 × 100) / (1500 × 2) = 10%
Q5. What is the probability of getting a head when a coin is tossed?
(a) 1/2
(b) 1/3
(c) 2/3
(d) 1/4
S5. Ans: (a) 1/2
Sol:
A coin has 2 sides. Probability of getting a head = 1/2.
Q6. A person buys an article for ₹1200 and sells it for ₹1500. What is the percentage profit?
(a) 20%
(b) 25%
(c) 30%
(d) 35%
S6. Ans: (b) 25%
Sol:
Profit = ₹1500 – ₹1200 = ₹300
Percentage profit = (Profit / Cost Price) × 100 = (300/1200) × 100 = 25%
Q7. If the ratio of two numbers is 3:4 and their LCM is 84, what is the product of these numbers?
(a) 778
(b) 578
(c) 588
(d) 688
S7. Ans: (c) 588
Sol:
Let the numbers be 3x and 4x. Their LCM = 12x.
Given LCM = 84, 12x = 84
x = 7
The product = 3x × 4x = 3 × 4 × 7² = 588
Q8. What is the HCF of 48 and 180?
(a) 12
(b) 18
(c) 16
(d) 24
S8. Ans: (a) 12
Sol:
Prime factorization of 48 = 2⁴ × 3
Prime factorization of 180 = 2² × 3² × 5
HCF = 2² × 3 = 12
Q9. If a person can complete a job in 10 days and another person in 15 days, how long will it take them to complete the job together?
(a) 6 days
(b) 5 days
(c) 9 days
(d) 8 days
S9. Ans: (a) 6 days
Sol:
Work rate of person 1 = 1/10
Work rate of person 2 = 1/15
Combined rate = 1/10 + 1/15 = 5/30 + 2/30 = 7/30
Time = 30/7 ≈ 4.29 days
Q10. A boat can travel 60 km downstream in 4 hours and the same distance upstream in 6 hours. What is the speed of the stream?
(a) 4 km/h
(b) 3 km/h
(c) 2 km/h
(d) 5 km/h
S10. Ans: (b) 3 km/h
Sol:
Speed downstream = 60/4 = 15 km/h
Speed upstream = 60/6 = 10 km/h
Speed of the stream = (15 – 10) / 2 = 5/2 = 2.5 km/h
Q11. The compound interest on ₹15000 for 2 years at 10% per annum is closest to:
(a) ₹3150
(b) ₹3120
(c) ₹3300
(d) ₹3250
S11. Ans: (a) ₹3150
Sol:
CI = P(1 + r/n)ⁿᵗ – P
CI = 15000(1 + 0.1)² – 15000 = ₹3150
Q12. A train covers a distance of 300 km at a speed of 60 km/h. How long does it take to cover the distance?
(a) 4 hours
(b) 5 hours
(c) 6 hours
(d) 7 hours
S12. Ans: (c) 5 hours
Sol:
Time = Distance / Speed = 300 / 60 = 5 hours
Q13. If a person sells an article at a loss of 10% for ₹1800, what was the cost price?
(a) ₹2000
(b) ₹2100
(c) ₹2200
(d) ₹2400
S13. Ans: (a) ₹2000
Sol:
Let the cost price be ₹x.
Loss = 10%
Selling Price (SP) = x – 10% of x = 0.9x = 1800
x = 1800 / 0.9 = ₹2000
Q14. Find the square root of √1764+√225.
(a) 57
(b) 42
(c) 44
(d) 45
S14. Ans: (a) 57
Sol:
√1764+√225. = 42+ 15=57
Q15. A tank can be filled by a tap in 8 hours but it leaks and takes 10 hours. How much time will it take to fill the tank with the leak?
(a) 40 hours
(b) 50 hours
(c) 60 hours
(d) 30 hours
S15. Ans: (a) 40 hours
Sol:
Rate of filling = 1/8, Rate of leakage = 1/10
Net rate = 1/8 – 1/10 = (5 – 4) / 40 = 1/40
Time to fill = 40 hours
