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Top 30 MCQs For Odisha B.Ed paper-II (Science) Entrance Exam 25 July 2024

Preparing for the Odisha B.Ed entrance exam can be challenging, especially for the Science section of Paper-II. To aid your preparation, we have compiled the top 30 multiple-choice questions (MCQs) that cover a broad range of topics essential for the exam. Each question is designed to test your knowledge and understanding of key scientific concepts.

Top 30 MCQs For Odisha B.Ed paper-II (Science) Entrance Exam

  1. Who proposed the cell theory?
    A) Anton van Leeuwenhoek
    B) Matthias Schleiden and Theodore Schwann
    C) Rudolf Virchow
    D) Robert Brown
    Answer: (B) Matthias Schleiden and Theodore Schwann
    Explanation: Matthias Schleiden and Theodore Schwann proposed the cell theory collaboratively in the 1830s.
  2. What is the cell theory?
    A) Cells are the building blocks of tissues.
    B) Cells can only arise from pre-existing cells.
    C) Cells are composed of membrane-bound organelles.
    D) Cells can exist independently of each other.
    Answer: B) Cells can only arise from pre-existing cells.
    Explanation: The cell theory states that cells can only arise from pre-existing cells through division.
  3. Which organelle is responsible for protein synthesis?
    A) Mitochondria
    B) Lysosomes
    C) Endoplasmic reticulum
    D) Golgi complex
    Answer: C) Endoplasmic reticulum
    Explanation: The endoplasmic reticulum (ER) is responsible for protein synthesis in cells.
  4. Which scientist is credited with the development of binomial nomenclature?
    A) Charles Darwin
    B) Gregor Mendel
    C) Carolus Linnaeus
    D) Louis Pasteur
    Answer: C) Carolus Linnaeus
    Explanation: Carolus Linnaeus developed the system of binomial nomenclature.
  5. What does the term “taxon” refer to?
    A) A species
    B) A category or rank within the taxonomic hierarchy
    C) An individual organism
    D) A genus
    Answer: B) A category or rank within the taxonomic hierarchy
    Explanation: Taxon refers to a category or rank within the taxonomic hierarchy, such as species, genus, or family.
  6. What does the taxonomic hierarchy represent?
    A) The evolutionary history of organisms
    B) The geographical distribution of organisms
    C) The classification of organisms into hierarchical categories
    D) The ecological interactions among organisms
    Answer: C) The classification of organisms into hierarchical categories
    Explanation: The taxonomic hierarchy represents the classification of organisms into hierarchical categories based on their relationships.
  7. What inhibits certain processes like nitrogen fixation by bacteria?
    A) Oxygen
    B) Carbon dioxide
    C) Ozone
    D) Nitrogen
    Answer: A) Oxygen
    Explanation: The presence of oxygen inhibits certain processes like nitrogen fixation by bacteria, as stated in the chapter.
  8. What is the role of ozone in the upper atmosphere?
    A) It absorbs harmful solar radiation
    B) It increases greenhouse gas levels
    C) It prevents oxygen from reaching the Earth’s surface
    D) It promotes the formation of ozone holes
    Answer: A) It absorbs harmful solar radiation
    Explanation: Ozone in the upper atmosphere absorbs harmful solar radiation, preventing it from reaching the Earth’s surface.
  9. What has caused the depletion of the ozone layer?
    A) Carbon dioxide emissions
    B) Deforestation
    C) Man-made compounds like CFCs
    D) Nitrogen fixation
    Answer: C) Man-made compounds like CFCs
    Explanation: Man-made compounds like CFCs react with ozone molecules, leading to the depletion of the ozone layer.
  10. What is the primary process of returning oxygen to the atmosphere?
    A) Respiration
    B) Combustion
    C) Photosynthesis
    D) Decomposition
    Answer: C) Photosynthesis
    Explanation: Photosynthesis is the primary process of returning oxygen to the atmosphere, as mentioned in the chapter.
  11. What is the valency of oxygen?
    (a) +1
    (b) -1
    (c) +2
    (d) -2
    Ans. (d) -2
    Explanation: The valency of oxygen is -2.
  12. What is the combining capacity of an element called?
    (a) Atomic mass
    (b) Atomicity
    (c) Valency
    (d) Molecular mass
    Ans.(c) Valency
    Explanation: The combining capacity of an element is called valency.
  13. What is the chemical formula for carbon dioxide?
    (a) CO
    (b) CO2
    (c) C2O
    (d) CO3
    Ans.(b) CO2
    Explanation: The chemical formula for carbon dioxide is CO2.
  14. What is the formula unit mass of magnesium oxide (MgO)?
    (a) 20u
    (b) 40u
    (c) 56u
    (d) 16u
    Ans.(b) 40u
    Explanation: The formula unit mass of magnesium oxide (MgO) is 40u.
  15. Which of the following is an example of a combustion reaction?
    (a) 2H2 + O2 → 2H2O
    (b) C6H12O6 → 2C2H5OH + 2CO2
    (c) 2Na + Cl2 → 2NaCl
    (d) CH4 + 2O2 → CO2 + 2H2O
    Answer: (d) CH4 + 2O2 → CO2 + 2H2O
    Explanation: Combustion reactions involve the rapid reaction of a substance with oxygen, often producing heat and light.
  16. Which of the following is an example of a double displacement reaction?
    (a) 2H2 + O2 → 2H2O
    (b) 2H2O → 2H2 + O2
    (c) Fe + 2HCl → FeCl2 + H2
    (d) 2NaCl + Pb(NO3)2 → 2NaNO3 + PbCl2
    Answer: (d) 2NaCl + Pb(NO3)2 → 2NaNO3 + PbCl2
    Explanation: In a double displacement reaction, positive ions of two ionic compounds exchange places to form two new compounds.
  17. Which of the following is an example of a decomposition reaction?
    (a) 2H2 + O2 → 2H2O
    (b) 2H2O → 2H2 + O2
    (c) Fe + 2HCl → FeCl2 + H2
    (d) 2NaCl + Pb(NO3)2 → 2NaNO3 + PbCl2
    Answer: (b) 2H2O → 2H2 + O2
    Explanation: In a decomposition reaction, a single compound breaks down into two or more simpler substances.
  18. What type of collision results in a loss of kinetic energy?
    (A) Elastic collision
    (B) Inelastic collision
    (C) Perfectly elastic collision
    (D) Perfectly inelastic collision
    Answer: (B) Inelastic collision
    Explanation: In an inelastic collision, kinetic energy is not conserved, resulting in a loss of kinetic energy as objects stick together or deform upon impact.
  19. What does the impulse-momentum theorem relate?
    (A) The change in momentum of an object to the impulse acting on it
    (B) The change in kinetic energy of an object to the impulse acting on it
    (C) The force acting on an object to its momentum
    (D) The force acting on an object to its acceleration
    Answer: (A) The change in momentum of an object to the impulse acting on it
    Explanation: The impulse-momentum theorem relates the change in momentum of an object to the impulse acting on it during a collision. Mathematically, it is expressed as Δp=F⋅Δt, where Δp is the change in momentum, F is the force, and Δt is the time interval over which the force acts.
  20. What is the mathematical expression for average power?
    (A) P= W / t
    (B) P= W / Δt
    (C) P= F⋅d
    (D) P= F⋅v
    Answer: (A) P= W / t
    Explanation: Average power is defined as the ratio of work done to the total time taken. Mathematically, it is expressed as P= W / t , where P is power, W is work, and t is time.
  21. If 2:3 is the same as 6:x, what is the value of x?
    A) 8
    B) 9
    C) 12
    D) 18
    ANS:- B) 9
    Sol:- To find the value of x, we can set up a proportion using the given ratios:
    2 : 3 = 6 : x
    We can solve this proportion by cross-multiplication:
    2 / 3 = 6 / x
    2 x x = 6 x 3
    2x = 18
    Dividing both sides by 2 to solve for x:
    2x / 2 = 18 / 2
    x = 9
    So, the value of x is 9
    Therefore, the correct answer is B) 9.
  22. If a recipe calls for 2 cups of flour for every 1 cup of sugar, what is the ratio of flour to sugar?
    A) 2:1
    B) 1:2
    C) 3:1
    D) 1:3
    ANS:- A) 2:1
    Sol:- In the given recipe, the ratio of flour to sugar is 2 cups of flour for every 1 cup of sugar. So, the ratio of flour to sugar is 2:1. The correct answer is A) 2:1.
  23. What is the simplified form of the ratio 12:18?
    A) 1:2
    B) 2:3
    C) 3:4
    D) 4:5
    ANS:- B) 2:3.
    Sol:- To simplify the ratio 12:18, we can divide both terms by their greatest common divisor, which is 6.
    12 / 6:18 / 6 = 2:3
    So, the simplified form of the ratio 12:18 is 2:3.
    Therefore, the correct answer is option B) 2:3.
  24. Find the area of a parallelogram with a base of 12 cm and a height of 8 cm.
    A) 80 square cm
    B) 96 square cm
    C) 100 square cm
    D) 64 square cm
    ANS:- B) 96 square cm.
    Sol:- The area A of a parallelogram is given by the formula:
    A = base × height
    Given:
    Base = 12 cm
    Height = 8 cm
    Substituting these values into the formula:
    A = 12 × 8
    A = 96square cm
    So, the area of the parallelogram with a base of 12 cm and a height of 8 cm is 96 square cm
    Therefore, the correct option is B) 96 square cm.
  25. What is the formula for the volume of a cone?
    A) πrl
    B) πr²h
    C) 1/3 πr²h
    D) 4/3 πr³
    ANS:- C) 1/3 πr²h
    Sol:- The correct formula for the volume of a cone is 1/3πr²h, where r is the radius of the base of the cone and h is the height of the cone. This formula represents the volume of a cone as one-third of the product of the base area (πr²) and the height (h). So the correct answer is C) 1/3 πr²h
  26. Calculate the volume of a cone with a radius of 6 cm and a height of 9 cm. (Take π = 3.14)
    A) 254.52 cubic cm
    B) 339.12 cubic cm
    C) 377.52 cubic cm
    D) 452.16 cubic cm
    ANS:- B) 339.12 cubic cm
    Sol:- The formula for the volume of a cone is given by: Volume= 1/3 πr²h
    Where: r is the radius of the base of the cone h is the height of the cone π is approximately 3.14
    Given that the radius r is 6 cm and the height h is 9 cm, we can plug these values into the formula:
    Volume = 1/3 × 3.14 × 6² × 9
    Volume = 1/3 × 3.14 × 36 × 9
    Volume = 1/3 × 3.14×324
    Volume = 1017.36 / 3
    Volume = 339.12 cubic cm
    So, the volume of the cone with a radius of 6 cm and a height of 9 cm is 339.12 cubic cm.
    Therefore, the correct option is B) 339.12 cubic cm.
  27. A flagpole casts a shadow of 10 meters when the angle of elevation of the sun is 45°. What is the height of the flagpole?
    a) 5 √2 meters
    b) 10 meters
    c) 10 √2 meters
    d) 20 meters
    ANS:- 10 meters
    Sol:- To find the height of the flagpole, we can use the trigonometric relationship between the height of the flagpole, the length of its shadow, and the angle of elevation of the sun.
    Let h be the height of the flagpole, and s be the length of its shadow.
    Given that the angle of elevation of the sun is 45∘, we can use the tangent function:
    tan(45∘) = h/ s
    ​Since tan(45∘) = 1, we have:
    1 = h/ 10
    Multiplying both sides by 10, we get:
    h = 10
    So, the height of the flagpole is 10 meters, which matches option b) 10 meters
  28. What is the relationship between the sine and cosine functions according to the Pythagorean identity?
    a) sin2θ + cos2θ =1
    b) 1 + tan2θ = sec2θ
    c) 1 + cot2θ = csc2θ
    d) sin(90°−θ) =cosθ
    ANS:- a) sin2θ + cos2θ =1
    Sol:- The relationship between the sine and cosine functions according to the Pythagorean identity is: a) sin2θ + cos2θ =1
    This is known as the Pythagorean identity for trigonometric functions, which states that in a right triangle, the square of the length of the side adjacent to an angle added to the square of the length of the side opposite to that angle equals the square of the length of the hypotenuse.
    So, the correct answer is option a) a) sin2θ + cos2θ =1
  29. A ladder leans against a wall at an angle of 60° to the horizontal. If the foot of the ladder is 6 meters away from the wall, how high does the ladder reach on the wall?
    a) 3√3 meters
    b) 6 √3 meters
    c) 6 meters
    d) 12 meters
    ANS:- b) 3√3
    Sol:- To find the height the ladder reaches on the wall, we can use trigonometry. The ladder, the wall, and the ground form a right triangle, where the ladder is the hypotenuse.
    Given:
    Angle of elevation = 60°
    Distance from the foot of the ladder to the wall = 6 meters
    Let h be the height the ladder reaches on the wall.
    Using the sine rule:
    sin(60∘) = h/length of the ladder
    We know that the length of the ladder is the hypotenuse of the right triangle, which is also the distance from the foot of the ladder to the wall.
    length of the ladder = 6
    h = sin(60∘) × 6
    h = (√3 / 2) × 6
    h = 3√3
    So, the height the ladder reaches on the wall is 3√3
    ​meters, which matches option b) 3√3
  30. In a right triangle, if the length of one leg is 5 units and the length of the hypotenuse is 10 units, what is the measure of the angle of elevation?
    a) 30°
    b) 45°
    c) 60°
    d) 90°
    ANS:- a) 30∘
    Sol:- To find the measure of the angle of elevation in a right triangle given the lengths of one leg and the hypotenuse, we can use the trigonometric ratio of sine.
    In a right triangle, the sine of an angle is the ratio of the length of the side opposite to that angle to the length of the hypotenuse.
    Given:
    Length of one leg (opposite side) = 5 units
    Length of the hypotenuse = 10 units
    Let’s denote the angle of elevation as θ.
    Using the sine ratio:
    sin(θ) = Opposite/Hypotenuse
    sin(θ) = 5/10
    sin(θ) = 1/2
    To find the angle whose sine is 1/2​, we can use the inverse sine function (also known as arcsine or sin−1).
    θ = sin−1 (½)​
    θ = 30∘
    So, the measure of the angle of elevation is θ = 30∘, which corresponds to option a) 30∘

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