CUET PG Life Science Previous Year Question Paper, Download Year Wise PYQs Here

CUET PG Life Science Previous Year Question Paper :The National Testing Agency has scheduled the conduction of the CUET PG Life Science Exam 2025 on March 27, 2025. All the students who are preparing to appear in the exam must now complete their preparations for the exam by understanding all the topics mentioned in the CUET PG Life Science Syllabus 2025.

Solving the CUET PG Previous Year Question Paper is one of the most important and crucial steps that students need to pursue in the process to complete their preparations for the exam along with solving the CUET PG Mock Test 2025. Scroll down in the article below to download CUET PG Life Science Question Paper 2024, 2023, 2022, etc.

CUET PG Life Science Previous Year Question Paper

The CUET PG Life Science Question Paper 2025 will be comprised of 75 questions to be answered by questions within the duration of 90 minutes. The students need to note that the questions will be asked in the multiple-choice questions format therefore they will have to select the right answer among the provided options. The question papers are a true representation of the main question paper as it helps students understand the types of questions, total number of questions, format of questions, etc.

CUET PG Life Science Previous Year Question Paper Download PDF

One of the most important parts of CUET PG Exam Preparations for students is to solve the CUET PG Previous Year Question Papers as they guide students with the exam pattern being followed over the years, types of questions being asked and repeated, etc. The table below shares the link to download the CUET PG Life Science Question Paper 2024, 2023, 2022, etc.

CUET PG Life Science Previous Year Questions with Answers

Q1. The portion of transmembrane proteins that cross the lipid bilayer are usually:

1. α-helices
2. β-sheet
3. Turns
4. Loops

Correct Answer:(1) α-helices.

Solution: The transmembrane regions of proteins are predominantly formed by α-helices due to their ability to interact favorably with the hydrophobic core of the lipid bilayer. Hydrophobic side chains extend outward to interact with the lipid bilayer, while the backbone hydrogen bonds stabilize the helix. β-sheets, in contrast, are typically seen in specific pore-forming structures like porins.

Q2. Match List I with List II:

1. (A) – (I), (B) – (III), (C) – (II), (D) – (IV)
2. (A) – (I), (B) – (II), (C) – (IV), (D) – (III)
3. (A) – (II), (B) – (IV), (C) – (III), (D) – (I)
4. (A) – (III), (B) – (IV), (C) – (I), (D) – (II)

Correct Answer:(2) (A) – (I), (B) – (II), (C) – (IV), (D) – (III).

Solution: Key Enzyme Functions:

• Cytochrome oxidase: Functions in the electron transport system, facilitating ATP synthesis.
• Topoisomerases: Change the linking number of DNA, aiding replication and transcription.
• Cohesins: Bind sister chromatids until segregation during cell division.
• PCNA: Proliferating cell nuclear antigen, essential for DNA replication and repair.

Q3. Which enzyme is inhibited by citrate in the Kreb’s cycle?

1. Phospho-fructo kinase II (PFKII)
2. Aldolase
3. Pyruvate kinase
4. Phosphoglycerate mutase (PGM)

Correct Answer:(1) Phospho-fructo kinase II (PFKII).

Solutions: Citrate acts as a feedback inhibitor for PFKII, a key regulatory enzyme in glycolysis. By inhibiting PFKII, citrate helps balance energy production between glycolysis and the Kreb’s cycle, ensuring efficient energy use.

Q4. Why does the presence of proline destabilize α-helix?

1. (A), (B), and (C) only
2. (A), (B), and (C), and (D)
3. (B), (C), and (D) only
4. (A), (B), and (D) only

Correct Answer:(1) (A), (B), and (C) only.

Solution: Key reasons for destabilization:

• (A): Proline introduces a sharp kink in the α-helix.
• (B): Its nitrogen atom is part of a rigid ring, preventing rotation around the N-C bond.
• (C): Proline lacks a substituent hydrogen for hydrogen bonding, a key stabilizer in α-helices.

Q5. Which of the following are components of lipid rafts in the plasma membrane?

1. (A) and (B) only
2. (A) and (C) only
3. (B) and (C) only
4. (C) and (D) only

Correct Answer:(1) (A) and (B) only.

Solution: Lipid rafts are specialized microdomains in the plasma membrane that are rich in cholesterol and sphingolipids. These domains play a significant role in cellular signaling, protein sorting, and trafficking. They are more ordered and tightly packed compared to the surrounding membrane but maintain fluidity.

Q6. Which enzyme is defective in galactosemia—a fatal genetic disorder in infants?

1. Glucokinase
2. Galactokinase
3. UDP-galactose 4-epimerase
4. Galactose-1-phosphate uridyltransferase

Correct Answer:(4) Galactose-1-phosphate uridyltransferase.

Solution: Galactosemia is caused by a deficiency in galactose-1-phosphate uridyltransferase (GALT). This enzyme converts galactose-1-phosphate into UDP-galactose, a critical step in galactose metabolism. Its deficiency results in toxic accumulation, causing severe complications like liver damage and developmental delays.

Q7. Match List I with List II and choose the correct answer from the options given below:

1. (A) – (I), (B) – (III), (C) – (II), (D) – (IV)
2. (A) – (III), (B) – (I), (C) – (IV), (D) – (II)
3. (A) – (II), (B) – (IV), (C) – (III), (D) – (I)
4. (A) – (IV), (B) – (III), (C) – (II), (D) – (I)

Correct Answer:(1) (A) – (I), (B) – (III), (C) – (II), (D) – (IV).

Solution: Key pairings for vitamins and disorders:

• Vitamin-A: Deficiency causes night blindness.
• Vitamin-D: A fat-soluble vitamin essential for bone health.
• Vitamin-C: Deficiency leads to scurvy.
• Vitamin-K: Necessary for blood clotting.

Q8. Identify the correct sequence of the given intermediates formed during glycolysis:

A. Fructose 1,6-biphosphate
B. Fructose 6-phosphate
C. Lactate
D. Phosphoenolpyruvate

Choose the correct answer from the options given below:

1. (A), (B), (C), (D)
2. (B), (A), (D), (C)
3. (A), (D), (B), (C)
4. (C), (D), (A), (B)

Correct Answer:(2) (B), (A), (D), (C).

Solution: The intermediates in glycolysis are formed in the sequence:

• Fructose 6-phosphate(B) →Fructose 1,6-biphosphate(A)
• Phosphoenolpyruvate(D) →Lactate(C) (under anaerobic conditions).

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